I want to type the letter-for-letter equivalence symbol. Here's what it looks like:
This is found in Adian's "The Burnside Problem and Identities in Groups". Thanks in advance.
This seems to be a good substitute:
\documentclass{article}
\usepackage{amsmath,graphicx}
\newcommand{\lfleq}{%
\mathrel{%
\vphantom{=}%
\ooalign{
$=$\cr
\hidewidth$\vcenter{\hbox{\scalebox{0.3}{\boldmath$\circ$}}}$\hidewidth\cr
}%
}%
}
\begin{document}
$A\lfleq B$
\end{document}
With a factor 0.4 you get
With stix2
you can use \eqcirc
.
\documentclass{article}
\usepackage{amsmath}
\usepackage{stix2}
\begin{document}
$A\eqcirc B$
\end{document}
The same \eqcirc
command is available to most math fonts with unicode-math
.
\documentclass{article}
\usepackage{amsmath}
\usepackage{unicode-math}
\begin{document}
$A\eqcirc B$
\end{document}
Unicode math declares \eqcirc
as U+02256, ≖. You can use it, but almost all fonts include it with the circle which touched the bars. If you want a little vertical space here (as in your image), you need to construct the relation symbol from two minus signs and the \circ
between them.
\fontfam[lm]
\def\myeqcirc{\mathrel{\vcenter{\offinterlineskip
\halign{\hfil$##$\hfil\cr-\cr \noalign{\kern-.48ex}
\scriptstyle\circ\cr\noalign{\kern-.12ex}-\cr\noalign{\kern-.5ex}}}}}
$A\eqcirc B$
$A\myeqcirc B$
\bye
First result is from Unicode math font Latin Modern and the second one is composed from two minus signs.